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  • https://doi.org/10.2140/pjm.1983.105.311Copy DOI Icon

Lifting group homomorphisms

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Abstract

If a knot K has Alexander polynomial different from 1, then its knot group, G maps onto some metacyclic group, Zr§Zp. We show that in that case, it also has a homomorphism onto a split extension of a free abelian group of rank p — 1 by Zr§Zp, and hence also onto a split extension of a direct sum of p — 1 cyclic groups of order s by the metacyclic group. In many cases, (such as if s is coprime with p), this group can be specified exactly. Otherwise there are a finite number of possibilities. A special case is Perko's result that a homomorphism of a knot group onto S3 = Z2^Z?) lifts to S4 = Z 2ίS)Z3<$(Z2 Θ Z2). As an application we obtain information about the derived series of G. In a final section it is shown how to associate a rational polynomial invariant to every metacyclic representation. 1. Lifting metacyclic representations. Let p be a prime, r a divisor of p — 1 and β a primitive rth root modulo p. Let E — Zj§Zp — (Y, S: γr zn sp = 19Y'1SY= Sβ). Up to isomorphism, the group is independent of β. Let G be the knot group of a knot, AT, in the 3-sphere, S3, and let φ be a homomoφhism of G onto E which takes a meridian, m, of K to YaSh. Then g.c.d. (α, r) — 1, since G is generated by conjugates of m. Setting X — YaSb and eliminating 7, we obtain a presentation

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