- Research Article
- 10.1515/math-2025-0228
On singular double phase problem with variable exponents and convolution term
- Jan 23, 2026
- Open Mathematics
- Rui He + 1 more +1
Abstract In this article, we consider the following singular double phase problem with variable exponents and convolution term of the form: − T p ( x ) , q ( x ) α ( x ) ( u ) = λ s ( x ) u − γ ( x ) + ∫ Ω | u ( x ) | h ( x ) | x − y | μ ( x , y ) | u ( y ) | h ( x ) − 2 u ( y ) in Ω , u = 0 on ∂ Ω , $$\begin{cases}-{\mathcal{T}}_{p\left(x\right),q\left(x\right)}^{\alpha \left(x\right)}\left(u\right)=\lambda s\left(x\right){u}^{-\gamma \left(x\right)}+\left({\int }_{{\Omega}}\frac{\vert u\left(x\right){\vert }^{h\left(x\right)}}{\vert x-y{\vert }^{\mu \left(x,y\right)}}\right)\vert u\left(y\right){\vert }^{h\left(x\right)-2}u\left(y\right) \text{in} {\Omega},\hfill \\ u=0 \text{on} \partial {\Omega},\hfill \end{cases}$$ where the operator T p ( x ) , q ( x ) α ( x ) ( u ) : = div ∇ u p ( x ) − 2 ∇ u + α ( x ) ∇ u q ( x ) − 2 ∇ u ${\mathcal{T}}_{p\left(x\right),q\left(x\right)}^{\alpha \left(x\right)}\left(u\right) : =\text{div}\left({\left\vert \nabla u\right\vert }^{p\left(x\right)-2}\nabla u+\alpha \left(x\right){\left\vert \nabla u\right\vert }^{q\left(x\right)-2}\nabla u\right)$ is the double phase operator with variable exponents, Ω ⊂ R N ${\Omega}\subset {\mathbb{R}}^{N}$ is a bounded domain with smooth boundary ∂Ω, 0 ≤ α (⋅) ∈ L ∞ (Ω), λ is a positive real parameter. The functions s ( x ) ∈ C ( Ω ̄ ) $s\left(x\right)\in C\left(\bar{{\Omega}}\right)$ are positive with compact support in Ω, h : R N → R $h : {\mathbb{R}}^{N}\to \mathbb{R}$ and μ : R N × R N → R $\mu : {\mathbb{R}}^{N}{\times}{\mathbb{R}}^{N}\to \mathbb{R}$ are continuous functions. Under the suitable conditions, the existence of at least one weak solution is obtained for the above problem by using the Nehari manifold approach. The novelty of this paper is that this problem includes singular term and convolution term. Moreover, the emergence of p ( x ) and q ( x ) Laplacian operator makes the study of this problem more complicated and interesting.
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